Q. 55.0( 1 Vote )

# Three dice are th

As 3 dice are thrown. So total possible outcomes = 6×6×6 = 216

For getting 15 as the sum we need this combination-

(5, 5, 5) or (6,4,5) or (6,6,3)

(6, 4, 5) can be arranged in 3! = 6 ways.

(6, 4, 5) can be arranged in (3!)/(2!) = 3 ways

10 favourable outcomes are possible.

P(E) = 10/216

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