Q. 5

The length of a rectangle is thrice its breadth and the length of its diagonal is 8√10 cm. The perimeter of the rectangle isA. 15√10 cmB. 16√10 cmC. 24√10 cmD. 64 cm

Given: Length of rectangle (l) = 3 × breadth(b) = 3b

Diagonal of rectangle = 8√10 m

We know that,

Base2 + Perpendicular2 = Hypotenuse2

b2 + (3b)2 = (8√10) 2

b2 + 9b2 = 640

10b2 = 640

b2 = 64

b = 8 cm

Therefore,

l = 3b = 24 cm

Hence,

Perimeter of a rectangle = 2(length + breadth)

= 2(24 + 8)

= 64 cm

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