The construction of a ΔABC in which AB = 6 cm, ∠A = 45° is possible when (BC + AC) is
A. 7 cm
B. 5.8 cm
C. 5 cm
D. 4.9 cm
For any triangle sum of the lengths of two sides is always greater than the length of third side.
So, BC + AC should be greater than 6 cm. Hence, BC + AC = 7 cm
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