Q. 5

# Taking p(x) = 3x2 – 2x + 4, write the following as polynomials:i) (x + 1) p(x) + (x – 1) p(x)ii) (x + 1) p(x) – (x – 1) p(x)iii) (i) p(x) = 3x2 – 2x + 4

Now,

(x + 1) p(x) + (x – 1) p(x)

taking p(x) common

p(x)[x + 1 + x-1]

2x × p(x)

2x × (3x2 – 2x + 4)

6x3 – 4x2 + 8x

(ii) p(x) = 3x2 – 2x + 4

Now,

(x + 1) p(x) - (x – 1) p(x)

taking p(x) common

p(x)[x + 1-x + 1]

2 × p(x)

2 × (3x2 – 2x + 4)

6x2 – 4x + 8

(iii) p(x) = 3x2 – 2x + 4

Now, taking p(x) common p(x)

3x2 – 2x + 4

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