Q. 55.0( 2 Votes )

<span lang="EN-US

Answer :

Let us consider Δ ABC and ACD is and exterior angle


To show: ACD = A + B


Through C draw CE parallel to AB


Proof:


A = y (AB || CE and AD is a transversal)


B = x (AB || CE and AC is a transversal; alternate angles are equal)


1 + 2 = x + y


Now, x + y = ACD


Hence, 1 + 2 = ACD


ACD = A + B


Hence Proved.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Understanding QuadrilateralUnderstanding QuadrilateralUnderstanding Quadrilateral40 mins
Champ Quiz | Polygons (Quadrilaterals)Champ Quiz | Polygons (Quadrilaterals)Champ Quiz | Polygons (Quadrilaterals)30 mins
Basic Understanding of PolygonsBasic Understanding of PolygonsBasic Understanding of Polygons44 mins
Area of PolygonsArea of PolygonsArea of Polygons41 mins
RD Sharma | Understanding Shapes (Polygons) Part 1RD Sharma | Understanding Shapes (Polygons) Part 1RD Sharma | Understanding Shapes (Polygons) Part 142 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

<span lang="EN-USKerala Board Mathematics Part I

<span lang="EN-USKerala Board Mathematics Part I

<span lang="EN-USKerala Board Mathematics Part I

<span lang="EN-USKerala Board Mathematics Part I

<span lang="EN-USKerala Board Mathematics Part I

<span lang="EN-USKerala Board Mathematics Part I

<span lang="EN-USKerala Board Mathematics Part I

<span lang="EN-USKerala Board Mathematics Part I

<span lang="EN-USKerala Board Mathematics Part I

<span lang="EN-USKerala Board Mathematics Part I