Answer :
We know that we can express any 2 digit number as 10m+n , where m is the digit at tens place and n is the digit at ones place.
∴ the number ending with 3 can be expressed as 10m+3.
(10m + 3)2 = (10m)2 + 2×10m×3 + 32 …………using, (x+y)2 = x2 + 2xy + y2
= 100m2 + 10× 6m + 9
Clearly, we can observe that the square ends in 9.
The number ending with 5 can be expressed as 10m+5.
(10m + 5)2 = (10m)2 + 2×10m×5 + 52 …………using, (x+y)2 = x2 + 2xy + y2
= 100m2 + 100m + (25)
= 100 (m2 + m) + (10×2 + 5 )
Clearly, we can observe that the square ends in 5.
The number ending with 4 can be expressed as 10m+4.
(10m + 4)2 = (10m)2 + 2×10m×4 + 42 …………using, (x+y)2 = x2 + 2xy + y2
= 100m2 + 10× 8m + (16)
= 100m2 + 10× 8m + (10 + 6)
= 100 m2 + 10× (8m+1) + 6
Clearly, we can observe that the square ends in 6.
Rate this question :






















<span lang="EN-US
Kerala Board Mathematics Part I<span lang="EN-US
Kerala Board Mathematics Part I<span lang="EN-US
Kerala Board Mathematics Part I<span lang="EN-US
Kerala Board Mathematics Part I<span lang="EN-US
Kerala Board Mathematics Part I<span lang="EN-US
Kerala Board Mathematics Part I<span lang="EN-US
Kerala Board Mathematics Part I<span lang="EN-US
Kerala Board Mathematics Part I<span lang="EN-US
Kerala Board Mathematics Part I<span lang="EN-US
Kerala Board Mathematics Part I