Answer :

Let ABC be a triangle, with BC = 6 cm and angles at its ends are ABC = 40° and ACB = 65° respectively.


Draw AP BC, such that APB and APC are right-angled triangles,


Let AP = 'h' cm


BP = 'x' cm and PC = (6 - x) cm



In ΔAPB,






…[1]


In ΔAPC






2.1445(6 - x) = h


= h [From 1]


12.867 - 2.556h = h


3.556h = 12.867


h = 3.618 cm


Also, area of a triangle




area(ΔABC) = 3 × 3.618


= 10.854 cm2 [appx]


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