Q. 55.0( 2 Votes )
Mark the correct alternative in each of the following:
Let the function f : R – {–b} → R – {1} be defined by
then
A. f is one-one but not onto
B. f is onto but not one-one
C. f is both one-one and onto
D. none of these
Answer :
Given that f: R – {–b} → R – {1} where
Here, f(x) = f(y) only when x=y.
Hence, it is one-one.
Now, f(x) = y
⇒ x + a = y(x + b)
⇒ x – yx = yb – a
So, x ϵ R – {1}
Hence, it is onto.
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