# Mark the correct alternative in each of the following:Let the function f : R – {–b} → R – {1} be defined by thenA. f is one-one but not ontoB. f is onto but not one-oneC. f is both one-one and ontoD. none of these

Given that f: R – {–b} R – {1} where

Here, f(x) = f(y) only when x=y.

Hence, it is one-one.

Now, f(x) = y

x + a = y(x + b)

x – yx = yb – a

So, x ϵ R – {1}

Hence, it is onto.

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