Q. 54.0( 4 Votes )

# Let l be the lower-class limit of a class-interval in a frequency distribution and m be the mid-point of the class. Then, find the upper-class limit f.

Answer :

**To Find:** Upper-Class limit

**Given:**

Lower class limit = l

Mid-point = m

**Concept Used:** Mid-Point is the average of the lower limit and upper limit.

**Explanation:**

We know that,

Cross-multiplying, we get,

l + u = 2m

u = 2m – l

**Hence, the upper limit is (2m – l).**

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