Q. 54.0( 54 Votes )

In figure 6.9, ce

Answer :


We draw a perpendicular on chord AB from O.


We know that a perpendicular drawn from the center of a circle on its chord bisects


the chord.


Therefore,


AM = MB …….(1)


OM is also perpendicular to chord PQ of smaller circle.


Therefore,


PM = MQ ………….(2)


Subtracting (2) from (1)


AM-PM = MB-MQ


AP = BQ


Hence Proved.


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