# In figure 2.30, p

From figure,

In ∆PAT, PAT = 900

TP2 = AT2 + PA2 …1

In ∆AST, SAT = 900

TS2 = AT2 + SA2 …2

In ∆QBT, QBT = 900

TQ2 = BT2 + QB2 …3

In ∆BTR, RBT = 900

TR2 = BT2 + BR2 …4

TS2 + TQ2 = AT2 + SA2 + BT2 + QB2 [Adding 2 and 3]

TS2 + TQ2 = AT2 + PA2 + BT2 + BR2 [SA = BR, QB = AP]

TS2 + TQ2 = TP2 + TR2 [From 1 and 4]

PROVED.

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