# In figure 2.22, r

Given ray AE ray BD. ray AF is bisector of EAB and ray BC is the bisector of Abd.

To find: line AF line BC

EAB = 2x (ray AF bisector EAB)

When a line, shape, or angle inti two exactly equal parts is called bisector.

ABD = 2y (ray BC bisector ABD)

Ray AE ray BD and Ab is transversal.

EAD ABD (alternate angle) two angle formed when a line crosses two other lines, that lie on opposite side of the transversal line and on opposite relative sides of the other lines. If the two lines crossed are parallel, the alternate angles are equal.)

2x = 2y

X = y

FAB ABC

But they form a pair of alternate angle that are congruent.

line AF line BC (hence proved)

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