Q. 54.0( 5 Votes )

In Fig. 2, AB is

Answer :

AOQ = 58° (given)

OBQ = 1/2 AOQ (angle in a semicircle)


OBQ = 1/2 × 58° = 29°


In Δ BAT,
ABQ + BAT + ATB = 180° (Sum of all the angles of a triangle)


29° + 90° + ATB = 180°


ATB = 61°


ATQ = 61°


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