Answer :

let the number at digit place be

So, da igit at tens place is 2x.


Number is 10×2x + x = 21x


Now interchanging the digits, at digit place we have 2x and at tens place x.number is 10×x + 2x = 12x


According to the given condition’s 12x + 21x = 66


33x = 66


Dividing both side by 33


X = 2


Digit at tens place is 2 × 2 = 4


Number is 42


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