In a frequency distribution, the mild-value of a class is 10 and width of each class is 6. The lower limit of the class is
Let the upper limit of class = u
Let lower limit of class = l
Mild value = 10 (given)
We know that,
Mild value = 1/2 (u + l)
10 = 1/2 (u + l)
= u + l = 20..............(i)
Width of class = 6 (given)
= u – l = 6 ................(ii)
Subtracting equation (ii) from equation (i), we get,
2l = 14
= l = 14/2 = 7.
lower limit = 7.
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