Answer :

Given that x + z = 2y and b^{2} = ac

We can write from x + z = 2y

…eq(1)

Now, b^{2} = ac

Now, we can write as

and …eq(2)

Now, LHS = a^{y–z} b^{z–x} c^{x–y}

= b^{0} = 1 = RHS

Therefore, LHS = RHS

Hence, proved .

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