Answer :


Let an isosceles ΔEFG in which the side FG is extended on both sides to form two exterior angles.


EF=FG


So, EFG=EGF…………(1)


As we know that sum of two interior angles is equal to the exterior angle of a triangle.


EFI=EFG+E…….(2)


EGJ=EGF+E…….(3)


Now, Subtracting equation (2) from (3)


EGJ-EFI=EGF+E-EFG-E


EGJ-EFI=EGF -EFG=0 (from (1))


EGJ-EFI=0


EGJ=EFI


Proved.


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