Q. 5

# If we produce the

Answer :

Let an isosceles ΔEFG in which the side FG is extended on both sides to form two exterior angles.

EF=FG

So, ∠EFG=∠EGF…………(1)

As we know that sum of two interior angles is equal to the exterior angle of a triangle.

∠EFI=∠EFG+∠E…….(2)

∠EGJ=∠EGF+∠E…….(3)

Now, Subtracting equation (2) from (3)

∠EGJ-∠EFI=∠EGF+∠E-∠EFG-∠E

⇒ ∠EGJ-∠EFI=∠EGF -∠EFG=0 (from (1))

⇒ ∠EGJ-∠EFI=0

⇒ ∠EGJ=∠EFI

Proved.

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