Answer :

Given A.P. is 9, 4, – 1, – 6, – 11, . . .

Where first term a = 9

Second term t_{1} = 4

Third term t_{2} = – 1

Common Difference d = t_{2} – t_{1} = – 1 – 4 = – 5

We know that, n^{th} term of an A.P. is

t_{n} = a + (n – 1)d

We need to find the 27^{th} term,

Here n = 27

Thus, t_{27} = 9 + (27 – 1)× ( – 5)

t_{27} = 9 + (26)× ( – 5) = 9 – 130 = – 121

Thus, t_{27} = – 121

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