Answer :
Given A.P. is 9, 4, – 1, – 6, – 11, . . .
Where first term a = 9
Second term t1 = 4
Third term t2 = – 1
Common Difference d = t2 – t1 = – 1 – 4 = – 5
We know that, nth term of an A.P. is
tn = a + (n – 1)d
We need to find the 27th term,
Here n = 27
Thus, t27 = 9 + (27 – 1)× ( – 5)
t27 = 9 + (26)× ( – 5) = 9 – 130 = – 121
Thus, t27 = – 121
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Arithmetic Progression and 'nth' Term of AP55 mins
Sum of n Terms of AP56 mins
Introduction of Geometric Progression60 mins
Imp Qs Practice For Boards (AP)59 mins
Arithmetic Progression and 'nth' Term of AP55 minsSum of n Terms of AP56 minsIntroduction of Geometric Progression60 minsImp Qs Practice For Boards (AP)59 minsTry our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
RELATED QUESTIONS :
Attempt any three
Maharashtra Board - Algebra PapersAttempt any four
Maharashtra Board - Algebra Papers<span lang="EN-US
Maharashtra Board - Algebra Papers<span lang="EN-US
Maharashtra Board - Algebra Papers<span lang="EN-US
Maharashtra Board - Algebra PapersAttempt any three
Maharashtra Board - Algebra Papers<span lang="EN-US
Maharashtra Board - Algebra Papers<span lang="EN-US
Maharashtra Board - Algebra PapersAttempt any three
Maharashtra Board - Algebra PapersAttempt any four
Maharashtra Board - Algebra Papers