Answer :
Given A.P. is 9, 4, – 1, – 6, – 11, . . .
Where first term a = 9
Second term t1 = 4
Third term t2 = – 1
Common Difference d = t2 – t1 = – 1 – 4 = – 5
We know that, nth term of an A.P. is
tn = a + (n – 1)d
We need to find the 27th term,
Here n = 27
Thus, t27 = 9 + (27 – 1)× ( – 5)
t27 = 9 + (26)× ( – 5) = 9 – 130 = – 121
Thus, t27 = – 121
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