Q. 54.0( 8 Votes )

Find the 27th term of the following A.P.

9, 4, – 1, – 6, – 11, . . .

Answer :

Given A.P. is 9, 4, – 1, – 6, – 11, . . .

Where first term a = 9


Second term t1 = 4


Third term t2 = – 1


Common Difference d = t2 – t1 = – 1 – 4 = – 5


We know that, nth term of an A.P. is


tn = a + (n – 1)d


We need to find the 27th term,


Here n = 27


Thus, t27 = 9 + (27 – 1)× ( – 5)


t27 = 9 + (26)× ( – 5) = 9 – 130 = – 121


Thus, t27 = – 121


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