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Given A.P. is 9, 4, – 1, – 6, – 11, . . .

Where first term a = 9

Second term t1 = 4

Third term t2 = – 1

Common Difference d = t2 – t1 = – 1 – 4 = – 5

We know that, nth term of an A.P. is

tn = a + (n – 1)d

We need to find the 27th term,

Here n = 27

Thus, t27 = 9 + (27 – 1)× ( – 5)

t27 = 9 + (26)× ( – 5) = 9 – 130 = – 121

Thus, t27 = – 121

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