Q. 54.5( 2 Votes )
Find n is the equation 52 × 54 × 56 × … × 52n = (0.008)-30.
Answer :
am× an = am + n
LHS = 52 × 54 × 56 × … × 52n
= 52 + 4 + 6 + …2n
= 52(1 + 2 + 3 + …n)
{1 + 2 + 3 + …n = }
=
= 5n(n + 1)
RHS = (0.008)-30 = (8× 10-3)-30
= (23× (2×5)-3)-30
= (23× 2-3× 5-3)-30
= 590
∵ (am)n = amn
LHS = RHS
∴ 5n(n + 1) = 590
∴ n(n + 1) = 90
∴n2 + n-90 = 0
Solving for n,
n = 9 and n = -10
But, n<0 is not possible
Hence, n = 9
Rate this question :






















Find n is the equation 52 × 54 × 56 × … × 52n = (0.008)-30.
Kerala Board Mathematics Part-1Find the sum of the first 25 terms of each of the arithmetic sequences below.
1, 6, 11, …
Kerala Board Mathematics Part-1Calculate the difference between the sum of the first 20 terms of the arithmetic sequences 6, 10, 14, … and 15, 19, 23, …
Kerala Board Mathematics Part-1The sum of the first 10 terms of an arithmetic sequence is 350 and the sum of the first 5 terms is 100. Write the algebraic expression for the sequence.
Kerala Board Mathematics Part-1Find the sum of the first 25 terms of each of the arithmetic sequences below.
11, 22, 33, …
Kerala Board Mathematics Part-1Find the sum of all three digit numbers, which are multiples of 9.
Kerala Board Mathematics Part-1Write four arithmetic sequences with 100 as the sum of the first four terms.
Kerala Board Mathematics Part-1Find the sum of the first 25 terms of each of the arithmetic sequences below.
12, 23, 34, ….
Kerala Board Mathematics Part-1Find the sum of the first 25 terms of each of the arithmetic sequences below.
19, 28, 37, …
Kerala Board Mathematics Part-1