# Draw an equilateral triangle with length of side 6.5 cm and let us draw a parallelogram equal in area to that triangle and having an angle 45°.

Steps of Construction:

1. We draw a triangle ABC of given dimensions. 2. We draw a perpendicular bisector of side AB which intersects AB at D.

3. Join C to D. 4. Draw a line parallel to AB through C by completing the parallelogram ACQB. 5. From D, construct GDB=45°.

6. The line cuts parallel line through C at E. 7. From E, cut an arc of length DB on the parallel line.

8. Mark the point as F.

9. Join F to B.

10. DBFE is the required parallelogram. Rate this question :

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