Q. 54.3( 22 Votes )

Draw an equilateral triangle with length of side 6.5 cm and let us draw a parallelogram equal in area to that triangle and having an angle 45°.

Answer :

Steps of Construction:


1. We draw a triangle ABC of given dimensions.



2. We draw a perpendicular bisector of side AB which intersects AB at D.


3. Join C to D.



4. Draw a line parallel to AB through C by completing the parallelogram ACQB.



5. From D, construct GDB=45°.


6. The line cuts parallel line through C at E.



7. From E, cut an arc of length DB on the parallel line.


8. Mark the point as F.


9. Join F to B.


10. DBFE is the required parallelogram.



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