Q. 54.4( 59 Votes )

Diagonals of a pa

Answer :

The figure is given below:


Given AO =5, BO = 12 and AB = 13


In Δ AOB, AO2 + BO2 = AB2


52 + 122 = 132


252 + 1442 = 1692


so by the Pythagoras theorem


Δ AOB is right angled at AOB.


But ∠ AOB + ∠ AOD forms a linear pair so the given parallelogram is rhombus whose diagonal bisects each other at 90°.

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