Answer :

List of natural number divisible by 4 between 1 to 140 is

4,8,12,…….136


Where first term a = 4


Second term t1 = 8


Third term t2 = 12


Thus, common difference d = t2 – t1 = 12 – 8 = 4


tn = 136


Now, By using nth term of an A.P. formula


tn = a + (n – 1)d


where n = no. of terms


a = first term


d = common difference


tn = nth terms


we can find value of “n” by substituting all the value in formula we get,


136 = 4 + (n – 1) × 4


136 – 4 = 4(n – 1)


132 = 4(n – 1)



n = 33 + 1 = 34


Now, By using sum of nth term of an A.P. we will find it’s sum



Where, n = no. of terms


a = first term


d = common difference


Sn = sum of n terms


Thus, Substituting given value in formula we can find the value of S34



S34 = 17 × [8 + 33×4]


S34 = 17 × [8 + 132]


S34 = 17 × 140 = 2380


Thus, S34 = 2380


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