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List of natural number divisible by 4 between 1 to 140 is

4,8,12,…….136

Where first term a = 4

Second term t1 = 8

Third term t2 = 12

Thus, common difference d = t2 – t1 = 12 – 8 = 4

tn = 136

Now, By using nth term of an A.P. formula

tn = a + (n – 1)d

where n = no. of terms

a = first term

d = common difference

tn = nth terms

we can find value of “n” by substituting all the value in formula we get,

136 = 4 + (n – 1) × 4

136 – 4 = 4(n – 1)

132 = 4(n – 1)

n = 33 + 1 = 34

Now, By using sum of nth term of an A.P. we will find it’s sum

Where, n = no. of terms

a = first term

d = common difference

Sn = sum of n terms

Thus, Substituting given value in formula we can find the value of S34

S34 = 17 × [8 + 33×4]

S34 = 17 × [8 + 132]

S34 = 17 × 140 = 2380

Thus, S34 = 2380

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