Q. 54.8( 10 Votes )

# A room is 6 m long, 4 m broad and 3 m high. Find the cost of laying tiles on its floor and four walls at the cost of Rs. 80/m^{2}.

Answer :

Given, a room with length, breadth, and height as 6 m, 4 m, and 3 m respectively and the cost of

laying tiles on its floor and four walls per m^{2} is Rs. 80.

We know, **Area of four walls = 2×(l+b)×h**

∴ Area of four walls = 2×(l+b)×h

= 2×(6+4)×3

= 2×10×3

= 60 m^{2}

Area of floor = length × breadth

= 6 × 4

= 24 m^{2}

∴ Cost of laying tiles on its floor and four walls at the rate of Rs. 80/m^{2}= 80×(60+24)

= Rs. 80×84

= Rs. 6720

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