Mark against the A. units
Given: Plane makes intercepts 3, -4 and 6 with the coordinate axes.
Formula Used: Equation of plane is where (x, y, z) is a point on the plane and a, b, c are intercepts on x-axis, y-axis and z-axis respectively.
Normal Form of a plane ⇒ lx + my + nz = p where (l, m, n) is the direction cosines and p is the distance of perpendicular to the plane from the origin.
Equation of the given plane is
i.e., 4x – 3y + 2z = 12 … (1)
which is of the form ax + by + cz = d
Direction ratios are (4, -3, 12)
Dividing (1) by 13,
which is in the normal form
Therefore length of perpendicular from the origin is units
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