Answer :

Let us take as and

Then above equations can be written as


14a + 3b = 5 (i)


21a - b = 2 (ii)


In this problem, we will eliminate ‘b’ from both the equations.


Multiplying equation (ii) with 3, we have




Putting the value of a in equation(i) gives b = 1


Now Since and It will form again a system of linear equations in x and y.




Rearranging the above equation


x + y = 7 (iii)


x – y = 1 (iv)



x = 4, putting the value of x in equation(iii) gives y = 3.


Hence the solution of the linear equation is x = and y = 3.


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