Q. 4 E5.0( 1 Vote )

# In each pair of p

Given, x2 – 1, xn – 1 pair of polynomials

Need to find out n such as first polynomial is factor of second

To check x2 – 1 is factor of xn – 1 we must get xn – 1 = 0 when substituted with x values from the first polynomial

Here, x2 – 1 so, x = √1 = 1

Consider n as 1 then the polynomial equation will be x1 – 1 which is equal to zero and x2 – 1 is the factor.

We get, 1 – 1 = 0

x2 – 1 is the factor of xn – 1

Hence, n = 1

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