1 A 1 A 1 B 1 B 1 C 1 C 1 D 1 D 1 E 1 E 1 F 1 F 2 2 3 A 3 A 3 B 3 B 3 C 3 C 4 A 4 A 4 B 4 B 4 C 4 C 4 D 4 D 4 E 4 E

Q. 4 D5.0( 2 Votes )

<span lang="EN-US

Class 8th Kerala Board Mathematics Part I 4. Identities

Answer :

(10.3 × 9.7) can be written as (10+0.3)(10-0.3)

using identity -

(10+0.3)(10-0.3) = -

= 100 - 0.09

= 99.91

now (10.7 × 9.3) can be written as (10+0.7)(10-0.7)

using identity -

(10+0.7)(10-0.7) = -

= 100 - 0.49

= 99.51

now putting values in question

(10.3 × 9.7) – (10.7 × 9.3) = 99.91 - 99.51

= 0.40

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