Q. 4 C5.0( 1 Vote )

# In each pair of p

Given, x + 1, xn – 1 pair of polynomials

Need to find out n such as first polynomial is factor of second

To check x + 1 is factor of xn – 1 we must get xn – 1 = 0 when substituted x with – 1 from the first polynomial

Consider n as 1 then the polynomial equation will be x – 1 which is not equal to zero and x + 1 will not be the factor.

Then consider n as 2 then x2 – 1 be the polynomial equation substitute x = – 1 in the equation

We get, (– 1)2 – 1 = 0

x + 1 is the factor of xn – 1

Hence, n = 2

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