Answer :
The figure is as follows:
Given:
A = (5, 4)
B = (-3, -2)
C = (1, -8)
Segment AD is the median
D is the midpoint of BC
By midpoint formula
x = -2 / 2
x = -1
y = -10 / 2
y = -5
D = (-1, -5)
Equation of median AD is given as follows:
y – y1 = m × (x – x1)
m = 9 / 6
6 × (y – 4) = 9 × (x – 5)
6y – 24 = 9x – 45
9x – 6y – 21 = 0
3x – 2y – 7 = 0
Therefore the equation of median AD = 3x – 2y – 7 = 0
Slope of Line AC
m = -12 / -4
m = 3
Since the line BP is parallel to AC.
The slope of line BP is same as that of slope of line AC = 3
Equation of line BP
y – y1 = m × (x – x1)
y + 2 = 3 × (x + 3)
y + 2 = 3x + 9
3x – y + 7 = 0
Therefore the equation of line BP = 3x – y + 7 = 0
Rate this question :


<span lang="EN-US
Maharashtra Board - Geometry Papers<span lang="EN-US
Maharashtra Board - Geometry Papers<span lang="EN-US
Maharashtra Board - Geometry PapersSolve any five su
Maharashtra Board - Geometry Papers<span lang="EN-US
Maharashtra Board - Geometry Papers<span lang="EN-US
Maharashtra Board - Geometry PapersSolve any two sub
Maharashtra Board - Geometry PapersSolve any four su
Maharashtra Board - Geometry Papers<span lang="EN-US
Maharashtra Board - Geometry Papers<span lang="EN-US
Maharashtra Board - Geometry Papers