Q. 4 B4.7( 7 Votes )

<span lang="EN-US

Answer :

Given: ax + by = 7 …(i)


bx + ay = 5 …(ii)


intersection point of equation (i) and (ii) is (3,1) which means point (3,1) lies on both the lines which concludes us that point (3,1) will satisfy both the equations


Therefore


3a + b = 7 …(iii)


3b + a = 5 a = 5 – 3b …(iv)


Putting a = 5 – 3b in equation (iii)


3 × (5 – 3b) + b = 7


15 – 9b + b = 7


15 – 8b = 7


8b = 15 – 7


8b = 8


b = 1


Put b = 1 in equation (iv)


a = 5 – (3 × 1)


a = 5 – 3


a = 2


Therefore a = 2 and b = 1


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Attempt of the foMaharashtra Board - Algebra Papers

<span lang="EN-USMaharashtra Board - Algebra Papers

Attempt any two sMaharashtra Board - Algebra Papers

<span lang="EN-USMaharashtra Board - Algebra Papers

<span lang="EN-USMaharashtra Board - Algebra Papers

<span lang="EN-USMaharashtra Board - Algebra Papers

Attempt any threeMaharashtra Board - Algebra Papers

Attempt any threeMaharashtra Board - Algebra Papers

<span lang="EN-USMaharashtra Board - Algebra Papers

<span lang="EN-USMaharashtra Board - Algebra Papers