Answer :
Let BC be height of the tree.
AB be the breadth of the river.
A be the initial position of the person
D be the final position of the person
∠CAB = 60° & ∠CDB = 30° & DA = 40m
Let AB = x & BC = h
In Δ DBC
⇒
⇒
⇒ ……. (1)
In Δ ABC
⇒
⇒
⇒ …… (2)
Using (1) & (2)
⇒
⇒
⇒
⇒
⇒ AB = 20m
⇒ BC =20√3 m =20×1.73 =34.6m
∴Height of the tree is 34.6m and width of the river is 20m.
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