Q. 4 A5.0( 1 Vote )

# In each pair of p

Given, x – 1, xn – 1 pair of polynomials

Need to find out n such as first polynomial is factor of second

To check x – 1 is factor of xn – 1 we must get xn – 1 = 0 when substituted x with 1 from the first polynomial

since, when x is substituted with 1 it will satisfy irrespective of n in the given polynomial

Consider n as 1 then the polynomial equation itself wiil be x – 1 and x – 1 will be the factor

Hence, n is 1

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