Q. 4 A3.7( 7 Votes )

# <span lang="EN-US

Answer :

Given:

Let X wins, P(X) = 2 × P(Y)

Y wins, P(Y) = 2 × P(Z)

Z wins, P(Z) = P(Z)

Assume Z wins 1 times,

P(Z) = 1

P(Y) = 2 × P(Z) = 2

P(X) 2 × P(Y) = 2 × 2 = 4

Now, Total probability P(S) = P(X) + P(Y) + P(Z)

= 1 + 2 + 4 = 7

Probability of X wins = 4/7

Probability of Y wins = 2/7

Probability of Z wins = 1/7

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