Q. 4 A5.0( 1 Vote )

Compute all angles of each of the figures below:


Answer :

Let us name the vertices of the triangle.


ABC + ABD = 180°


ABC + 145° = 180°


ABC = 180° - 145°


ABC = 35°


In Δ ABC,


A + B + C = 180°


A + 35° + 70° = 180°


A + 105° = 180°


A = 180° - 105°


A = 75°


CAF + CAB = 180°


CAF + 75° = 180°


CAF = 180° - 75°


CAF = 105°


BCE + BCA = 180°


BCE + 70° = 180°


BCE = 180° - 70°


BCE = 110°


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