Q. 495.0( 1 Vote )

In an isosceles Δ A. 30°

B. 45°

C. 60°

D. 90°

Answer :

AB2 = 2AC2


AB2 = AC2 + AC2


AB2 = AC2 + BC2


Therefore, it is an isosceles triangle right angled at C. C = 90°

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