Q. 495.0( 1 Vote )
In an isosceles Δ A. 30°
B. 45°
C. 60°
D. 90°
Answer :
AB2 = 2AC2
AB2 = AC2 + AC2
AB2 = AC2 + BC2
Therefore, it is an isosceles triangle right angled at C. ∠ C = 90°
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