Q. 484.0( 1 Vote )

Evaluate <span la

Answer :

Given,

Let cosx=t


-sinx dx=dt



Now, t2-2t-3


= t2-3t+t-3


= t(t-3)+t-3


= (t-3) (t+1)



1 A(t-1)+B(t-3)


Equating ’t’ coeff:-


0=A+B


A=-B


Equating constant:-


1=-A-3B


1=-(-B)-3B


1=-2B









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