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RD Sharma - Volume 1

19. Indefinite Integrals

Exercise 19.2

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Exercise 19.3

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Exercise 19.4

Exercise 19.5

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Exercise 19.6

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Exercise 19.7

Exercise 19.8

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Exercise 19.9

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Exercise 19.10

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Exercise 19.11

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Exercise 19.12

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Exercise 19.13

Exercise 19.14

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Exercise 19.15

Exercise 19.16

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Exercise 19.17

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Exercise 19.18

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Exercise 19.19

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Exercise 19.20

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Exercise 19.21

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Exercise 19.22

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Exercise 19.23

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Exercise 19.24

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Exercise 19.25

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Exercise 19.26

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Exercise 19.27

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Exercise 19.28

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Exercise 19.29

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Exercise 19.30

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Exercise 19.31

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Exercise 19.32

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Very short answer

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MCQ

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Revision exercise

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Q. 484.0( 1 Vote )

Evaluate <span la

Class 12th RD Sharma - Volume 1 19. Indefinite Integrals

Answer :

Given,

Let cosx=t

-sinx dx=dt

Now, t²-2t-3

= t²-3t+t-3

= t(t-3)+t-3

= (t-3) (t+1)

1≅ A(t-1)+B(t-3)

Equating ’t’ coeff:-

0=A+B

A=-B

Equating constant:-

1=-A-3B

1=-(-B)-3B

1=-2B

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