Q. 474.0( 2 Votes )

# Evaluate <span la

Answer :

Given, Now, 3x2+13x-10

= 3x2+15x-2x-10

= 3x(x+5)-2(x-5)

= (x-5) (3x-2) 1 A (3x-2) + B(x+5)

Equating ‘x’ coeff: -

0=3A+B

B=-3A

Equating constant:-

1=-2A+5B

1=-2A+5(-3A)

1=-2A-15A

1=-17A       Rate this question :

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