Let us suppose that two consecutive numbers are x and x + 1. According to the given condition, x2 + (x + 1)2= 145 x2 + x2+ 2x + 1 = 145 2x2 + 2x + 1 = 145 2x2 + 2x - 144 = 0 x2 + x - 72 = 0 x2 + 9x - 8x - 72 = 0 x(x + 9) - 8(x + 9) = 0 (x + 9) (x - 8) = 0 x = -9, 8 Accepting only positive number, we get Two number would be x = 8 and x + 1 = 9

Q. 465.0( 8 Votes )

Find two consecut

Class 10th

Answer :

Let us suppose that two consecutive numbers are x and x + 1.

According to the given condition,

x² + (x + 1)²= 145

x² + x²+ 2x + 1 = 145

2x² + 2x + 1 = 145

2x² + 2x - 144 = 0

x² + x - 72 = 0

x² + 9x - 8x - 72 = 0

x(x + 9) - 8(x + 9) = 0

(x + 9) (x - 8) = 0

x = -9, 8

Accepting only positive number, we get

Two number would be x = 8 and x + 1 = 9

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