Q. 465.0( 8 Votes )

Find two consecut

Answer :

Let us suppose that two consecutive numbers are x and x + 1.

According to the given condition,

x2 + (x + 1)2= 145

x2 + x2+ 2x + 1 = 145

2x2 + 2x + 1 = 145

2x2 + 2x - 144 = 0

x2 + x - 72 = 0

x2 + 9x - 8x - 72 = 0

x(x + 9) - 8(x + 9) = 0

(x + 9) (x - 8) = 0

x = -9, 8

Accepting only positive number, we get

Two number would be x = 8 and x + 1 = 9

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