Q. 454.1( 7 Votes )

In the given figure, AB || CD || EF, EA AB and BDE is the transversal such that DEF = 55°. Then AEB = ?


A. 35°

B. 45°

C. 25°

D. 55°

Answer :

According to question


AB || CD || EF and



So, D = B (Corresponding angles)


According to question CD || EF and BE is the traversal then,


D + E = 180 (Interior angle on the same side is supplementary)


So, D = 180 – 55 = 125o


And B = 125o


Now, AB || EF and AE is the traversal.


So, BAE + FEA = 180 (Interior angle on the same side of traversal is supplementary)


90 + x + 55 = 180


X + 145 = 180


X= 180 – 145 = 35o

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