# In the given figure, AB || CD || EF, EA ⊥ AB and BDE is the transversal such that ∠DEF = 55°. Then ∠AEB = ?A. 35°B. 45°C. 25°D. 55°

According to question

AB || CD || EF and

So, D = B (Corresponding angles)

According to question CD || EF and BE is the traversal then,

D + E = 180 (Interior angle on the same side is supplementary)

So, D = 180 – 55 = 125o

And B = 125o

Now, AB || EF and AE is the traversal.

So, BAE + FEA = 180 (Interior angle on the same side of traversal is supplementary)

90 + x + 55 = 180

X + 145 = 180

X= 180 – 145 = 35o

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