Answer :

Let the speed of the 1st car at point A and 2nd car at point B travelling in positive x - axis direction be x and y respectively.

Case 1: Same Direction

Distance Travelled by 1st and 2nd Car in 8 hours are 8x and 8y respectively.

Both the cars will meet outside of the points A and B which are 160 km apart. So, the 1st car will travel 160 km more distance from 2nd car meeting each other in 8 hours.

∴ 8x - 8y = 160

⇒ x - y = 20.....(1)

Case 2: Opposite Direction

Distance Travelled by 1st and 2nd Car in 2 hours are 2x and 2y respectively.

Both the cars will meet in between the points A and B which are 160 km apart. So, the sum of distance travelled by 1st car and distance travelled by 2nd car meeting each other in 2 hours is equal to 160 km.

∴ 2x + 2y = 160

⇒ x + y = 80.....(2)

Adding equations (1) and (2), we get -

2x = 100

∴ x = 50

substitute the value of x in equation (2), we get -

y = 30

Thus, the speed of 1st car = 50 km/h

and, the speed of 2nd car = 30 km/h

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