Q. 435.0( 1 Vote )

# In ΔABC, BD ⊥ AC, ∠CAE = 30° and ∠CBD = 40°. Then ∠AEB = ?A. 35°B. 45°C. 25°D. 55°

In triangle BDC,

B= 40, D = 90

So, C = 180 –(90 + 40)

= 50°

Now in triangle AEC,

C= 50, A = 30

So, E = 180 – (50 + 30)

= 100°

Thus, AEB = 180 – 100 (Sum of linear pair is 180°)

= 80°

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