Q. 435.0( 1 Vote )

In ΔABC, BD AC, CAE = 30° and CBD = 40°. Then AEB = ?


A. 35°

B. 45°

C. 25°

D. 55°

Answer :

In triangle BDC,


B= 40, D = 90


So, C = 180 –(90 + 40)


= 50°


Now in triangle AEC,


C= 50, A = 30


So, E = 180 – (50 + 30)


= 100°


Thus, AEB = 180 – 100 (Sum of linear pair is 180°)


= 80°

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