# In the given figure, sides CB and BA of ΔABC have been produced to D and E respectively such that ∠ABD = 110° and ∠CAE = 135°. Then ∠ACB = ?A. 35°B. 45°C. 55°D. 65°

ABC = 180 – 110 = 700 (Linear pair of angles)

BAC = 180 – 135 = 450 (Linear pair of angles)

So,

In Triangle ABC, we have

ABC + BAC + ACB = 180o

ACB = 180 – 70 – 45 = 650

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