Q. 425.0( 2 Votes )

In the given figure, sides CB and BA of ΔABC have been produced to D and E respectively such that ABD = 110° and CAE = 135°. Then ACB = ?


A. 35°

B. 45°

C. 55°

D. 65°

Answer :

ABC = 180 – 110 = 700 (Linear pair of angles)


BAC = 180 – 135 = 450 (Linear pair of angles)


So,


In Triangle ABC, we have


ABC + BAC + ACB = 180o


ACB = 180 – 70 – 45 = 650

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