Answer :

We know that,

Tangent drawn from an external point of a circle are equal

∴ OP = OQ = 10 cm

PQ = 5 + 5

= 10 cm

_{As OP = OQ = PQ}

_{∴} _{OP = OQ = OP = 10 cm}

_{Hence, POQ is an equilateral triangle as all the sides are equal to each other}

_{Also, angles of an equilateral triangle are of 60}^{o}

_{∴∠} _{POQ = 60}^{o}

_{Here, we have}

_{Side = 10 cm}

_{Radius, r = 5 cm}

⇒ θ = 60°

And, R = 10 cm

∴ Area of shaded region = Area of triangle OPQ + Area of semi-circle PBQM – Area of sector OPAQ

.

Hence, proved

Rate this question :

How useful is this solution?

We strive to provide quality solutions. Please rate us to serve you better.

Related Videos

Bonus Questions on Circles40 mins

How to Revise Chemistry45 mins

Nelson Mandela : Long Walk to Freedom42 mins

Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Expertsview all courses

Dedicated counsellor for each student

24X7 Doubt Resolution

Daily Report Card

Detailed Performance Evaluation