Q. 424.0( 4 Votes )

# A taxi charges Rs

Answer :

Total distance covered = x km

Total fare = Rs y

Charges for 1 km = Rs 20

Charges for 2 kms = Rs 20 + Rs 12

Charges for 3 kms = Rs 20 + Rs 12 × 2

Continuing, we get,

Charges for (x – 1) kms = Rs 20 + Rs 12 × (x – 2)

Charges for x kms = Rs 20 + Rs 12 × (x – 1)

Total fare = Rs y

Therefore,

Total fare = Charges for x kms

y = 20 + 12 × (x – 1)

y = 20 + 12x – 12

y = 12x + 8

Let x = 1 then, y = 12x + 8

y = 12× 1 + 8

y = 12 + 8

y = 20

Let x = 5 then, y = 12x + 8

y = 12× 5 + 8

y = 60 + 8

y = 68

Let x = 10 then, y = 12x + 8

y = 12× 10 + 8

y = 120 + 8

y = 128

Plotting, (1, 20), (5, 68) and (10, 128) on the graph we get,

The blue line indicates the required graph of y = 12x + 8

When x = 16, we take 16 on x axis.

Draw a line from 16 on x axis which is parallel to y axis and meets the blue line.

Clearly from the graph the value at y axis is 200

Therefore, taxi charges at covering 16 km = Rs 200

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