Three equal cubes A. 7 : 9

B. 49 : 81

C. 9 : 7

D. 27 : 23

Given,

Three equal cubes are placed adjacently in a row

Let edge of cubes = a

Hence , sum of surface area of 3 cubes = 3×6a² = 18 a²

So, length of cuboid thus formed = a+a+a = 3a

Breadth of cuboid = a

Height of cuboid = a

Total surface area of cuboid =

Hence ,