Q. 45.0( 1 Vote )

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We know that, distance between two parallel planes:

Ax + By + Cz + D1=0…… (1) and Ax + By + Cz + D2=0…… (2) is given by, Here, the two parallel planes are given as,

2x + 2y - z + 2=0 …………… (3)

and 4x + 4y - 2z + 5=0 i.e. 2x + 2y - z + =0 ………… (4)

Comparing equation (3) with equation (1) and equation (4) with equation (2) we get,

A=2, B=2, C= - 1, D1=2 and D2= .

So, the distance between the given two parallel planes are,      Hence, the distance between the parallel planes 2x + 2y - z + 2=0 and 4x + 4y - 6z + = is .

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