Answer :

Let PQ be a diameter of a circle with center O, AB and CD are two tangents drawn at the ends P and Q respectively.

To Show: AB || CD

Now, we know

Tangent at any point is perpendicular to the radius at the point of contact

⇒ OP ⊥ AB and OQ ⊥ CD

⇒ ∠OPA = ∠OQD [Both 90°]

⇒ AB || CD [If two lines are cut by a transversal and the alternate interior angles are equal, then the lines are parallel]

Hence, Proved.

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