# Let us show that

Let A (7, 9)

B (3, -7)

C (-3, 3)

be the vertices of a triangle.

We know that distance between two points (x1, y1) and (x2, y2) is given by .

Using the above distance formula,

AB

BC

CA

Now, (BC)2 + (CA)2

and (AB)2

We find that (BC)2 + (CA)2 = (AB)2

Hence the points (7, 9), (3, –7) and (–3, 3) are the vertices of a right angled triangle.

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