Answer :

Let A (7, 9)


B (3, -7)


C (-3, 3)


be the vertices of a triangle.


We know that distance between two points (x1, y1) and (x2, y2) is given by .


Using the above distance formula,


AB





BC





CA





Now, (BC)2 + (CA)2


and (AB)2


We find that (BC)2 + (CA)2 = (AB)2


Hence the points (7, 9), (3, –7) and (–3, 3) are the vertices of a right angled triangle.


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