Q. 44.2( 24 Votes )

# Let us show that

Answer :

Let A → (7, 9)

B → (3, -7)

C → (-3, 3)

be the vertices of a triangle.

We know that distance between two points (x_{1}, y_{1}) and (x_{2}, y_{2}) is given by .

Using the above distance formula,

AB

BC

CA

Now, (BC)^{2} + (CA)^{2}

and (AB)^{2}

We find that (BC)^{2} + (CA)^{2} = (AB)^{2}

Hence the points (7, 9), (3, –7) and (–3, 3) are the vertices of a right angled triangle.

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