# Let us show that,

Given:

3√48-4√75 + √192 = 0

Take L.H.S. = 3√48-4√75 + √192

It can be written as:

3√(2×2×2×2×3)-4√(3×5×5) + √(2×2×2×2×2×2×3)

= 12√3-20√3 + 8√3

= -8√3 + 8√3

= 0 = R.H.S.

Hence, L.H.S. = R.H.S.

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