Q. 44.4( 30 Votes )

In figure 3.80, i

Answer :

Given: PQ = 6, QR = 10, PS = 8


PT × PS = PR × PQ


This property is known as theorem of chords intersecting outside the circle.


PR = PQ + RQ = 6 + 10 = 16


PT × 8 = 16 × 6


PT = 12


TS = PT – PS = 12 – 8 = 4


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